A baseball pitcher throws a baseball with a speed of 46m/s. In throwing the baseball, the pitcher accelerates the ball through a displacement of about d=3.4m, from behind the body to the point where it is released.
2007-02-14 15:07:11 · 3 answers · asked by Vanita L 1 in Science & Mathematics ➔ Physics
All kinds of things are wrong here, the most problematic being the time it takes to move the 3.4m, the acceleration depending on that time.
There is also the problem that the ball is moving in an arc most of the time and the pitcher's body is moving. But even the simple assumption of a straight line requires a time.
2007-02-14 15:18:08 · answer #1 · answered by Mike1942f 7 · 0⤊ 0⤋
If you assume that the average speed of the ball before release is half of the final velocity. Then you can get the time it took to throw it. Then solve for m/sec/sec
2007-02-14 23:28:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋
u can try v^2 = 2*a*S formula
2007-02-14 23:33:10 · answer #3 · answered by novice 4 · 0⤊ 0⤋