How much time does it take for the package to reach the ground?

Question

A helicopter is ascending vertically with a speed of 6.00m/s. At a height of 115m above the Earth, a package is droppped from a window. [Hint: The package's initial speed equals the helicopter's.]

Answer 1

break it into two parts. The first being from initial velocity to zero at it's max height, the second from it's max height to the ground.

1) find time to reach max height
vf = vi + at
0 = 6.00 m/s + -9.8 m/s^2 x t
t = -6.00 m/s / (-9.8 m/s^2)
= 0.61 sec

2) find max height
h = Vi x t +1/2 a t^2
= 6.00 m/s x .61 sec + 1/2 x (-9.8 m/s^2) x (.61 sec)^2
= 1.84 meters higher than the 115 m you started at
so max height = 116.84 m

3) find time to drop from max height
h = Vi x t + 1/2 a t^2
116.84 m = 0 + 1/2 x 9.8 m/s^2 x t^2
t =4.88 sec

4) total time = t up to max height + t down from max height =
0.61 sec + 4.88 sec = 5.49 sec

Answer 2

This is a trick question right????? Don't you want to take into account the size and mass of the package. As an example a package of helium baloons with a negative weight would take a long time, also is the package in the downforce of the rotars? If so what is the weight of the helicopter and how much downforce is being produced?

Answer 3

Looking at the givens, you have an initial velocity (6.00 m/s), a distance (115 m), and since it's freefall (a = -9.8 m/s/s). Using this info, you will want to use d = Vit + .5at^2. Make sure you have your distance negative because it will go down. Once you plug in your numbers, you will see that you need to use the quadratic formula. Plug the necessary info into the quadratic formula, and you will get two answers. The positive answer is the answer you want to use, since we do not have flux capacitors to take advantage of a negative time. :)

Answer 4

i think its 12.34