How would i figure this out?!
2007-02-14 13:25:21 · 7 answers · asked by silverchair 1 in Science & Mathematics ➔ Other - Science
IN a rectangular shape, golden rectangular has maximum area.
Golden rectangular means leangth is always double to its width.
Assume length = L then width will be = L/2
3000 ft is the total circumference of the rectangle means
L + L/2 + L + L/2 = 3000
3L = 3000
hence L = 1000 ft
Size of the rectangular for maximum area covered
= 1000 ft X 500 ft
2007-02-14 13:33:29 · answer #1 · answered by Mritunjay 2 · 0⤊ 1⤋
The largest area to circumference ratio for a rectangle is a perfect square.
Thus the area enclosed would be (3000/4)^2 sqft.
Done.
2007-02-14 13:29:46 · answer #2 · answered by Jerry P 6 · 1⤊ 0⤋
60 times 50
2007-02-14 13:32:47 · answer #3 · answered by Anonymous · 0⤊ 1⤋
3000/ 4 = A
AxA= your answer
2007-02-14 13:42:42 · answer #4 · answered by brebitz 2 · 0⤊ 1⤋
permit e = length of section, w = width of section, A = part of rectangle, f = finished quantity of fencing. f = 2e+4w = 1200 e + 2w = six hundred e = six hundred - 2w A = e*w = (six hundred - 2w)*w = 600w - 2w^2 Take the spinoff of A. A' = six hundred - 4w Set A' equivalent to 0 and remedy for w. six hundred - 4w = 0 six hundred = 4w w = one hundred fifty A' is advantageous for w
2016-10-02 03:57:39 · answer #5 · answered by ? 4 · 0⤊ 0⤋
3000/4[sides]=750
750x750[lengthxwidth]=562500 square feet
2007-02-14 13:29:47 · answer #6 · answered by Anonymous · 1⤊ 0⤋
500,000sq.ft.
side A 1,000
side B 1,000
sideC 500
side D 500
sides=3,000ft.
500 x 1,000
= sq.ft.
2007-02-14 13:41:00 · answer #7 · answered by Anonymous · 0⤊ 1⤋