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2the square root of x * the root of x^3 divided by the square root of 9x^10

2007-02-14 12:53:05 · 2 answers · asked by Charnissia S 1 in Education & Reference Homework Help

2 answers

Let's try to rewrite this:

2sqrt(x)sqrt(x^3) / sqrt(9x^10)

If that's right, then here we go! First, you can't have a radical (sqrt) in the denominator of a fraction. We have to get rid of that, but let's see if we can simplify anything first. In your numerator, you have a few things that we can combine:

2sqrt(x)sqrt(x^3) = 2sqrt(x^4)
= 2x^2

You can simplify your denominator as well:

sqrt(9x^10) = 3x^5

So now you have:

2x^2 / 3x^5 = 2 / 3x^3

2007-02-17 11:31:47 · answer #1 · answered by igorotboy 7 · 0 1

2/9x^5 is what I got. idk if it's right. I think it is...

2007-02-14 21:02:34 · answer #2 · answered by Anonymous · 0 0

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