Okay, I need help!!
If there are 11 people that each has to shake hand with eachother, how many handshakes will there be? My answer is 55, but I am not sure! Please try to help me!!
2007-02-14 11:06:02 · 14 answers · asked by Anonymous in Education & Reference ➔ Homework Help
No, because if you did 110, you would have double handshakes! Do you get what I just said? Like, okay, so one person shakes hands with 10 people, but some people still have to shake hands with other people. You can't count them twice!
2007-02-14 11:12:06 · update #1
OMG, everyone who said 55, THANKS SOO MUCH!
It is going to be hard choosing the best answer, so do not feel like you didn't do anything, okay?? THANX EVERYONE!
2007-02-14 11:18:44 · update #2
It is 55. The first person shakes with 10 people. The second person has already shaked with the 1st so they shake with 9 others. The third shakes with 8, 4th with 7, etc. So you have 10+9+8+7+6+5+4+3+2+1+0 = 55.
2007-02-14 11:12:49 · answer #1 · answered by Anonymous · 0⤊ 0⤋
the first person has 10 different people to shake with, then the next 9, the next 8 and so forth. therefore 10 + 9 +8 +7 +6 +5 +4 +3 +2 + 1 = 55
You're right!
2007-02-14 11:13:41 · answer #2 · answered by Rachel G 1 · 0⤊ 0⤋
Uhh... hold on *doing mental math
121 handshakes...
why?
1 person shake 11 hands
2 people shake 22 hands
3 people shake 33 hands
---so forth
11 people X 11 = 121 handshakes.
You can also multiply it 11 X 11 and get 121... 11 people must shake 11 hands.
Where did you get 55?
2007-02-14 11:11:53 · answer #3 · answered by thehutch86 2 · 0⤊ 0⤋
That's easy!
10+9+8+7+6+5+4+3+2+1
because each time there's one less person for each person to hand shake, and they never have to shake hands with themself.
So it would be 55... like you said.
2007-02-14 11:13:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋
that is correct. If you got 11 people each having to shake hands with each other, there'll be 55 handshakes.
If you label 11 people from 'A' to 'K', and 'A' shakes hands with 'B' through 'K', and 'C' shakes hands with 'D' through 'K', and 'D' shakes hands with 'E' through 'K'...... and finally 'J' shakes hands with 'K', you will have a total of 55 handshakes.
'K' won't have to shake hands with anyone cause everyone will have already shaken hands with 'K'.
I don't know where half of the idiots are getting 121 handshakes. Apparently they sucked at math.
I'm 100% sure
2007-02-14 11:11:11 · answer #5 · answered by the_hells_that 2 · 1⤊ 0⤋
Create a table with the numbers 1 to 11 across the top, and the numbers 1 to 11 down the left side, and you can use it to check your answer, but I believe you have it. (1 does not shake hands with 1, and so forth; and people do not have to shake hands twice.)
2007-02-14 11:13:15 · answer #6 · answered by Gee Wye 6 · 0⤊ 0⤋
Okay, are we counting each individual's number of handshakes or handshakes total. Cause I'm figuring each person is shaking hands ten times-so would it be 110 total handshakes?
2007-02-14 11:09:27 · answer #7 · answered by every1lovesamixedgirl 4 · 0⤊ 1⤋
well let's see....
11 ppl, each person shakes hands w/ 10 other ppl (you wouldn't shake hands w/ yourself) ...... 11 ppl * 10 handshakes is 110. 110 handshakes
i'm pretty sure i'm right, if not then sorry. here you go.
2007-02-14 11:23:58 · answer #8 · answered by dreamer_girl 2 · 0⤊ 0⤋
I think its 55
2007-02-14 11:12:23 · answer #9 · answered by lowdrop2001 2 · 0⤊ 0⤋
121
2007-02-14 11:09:45 · answer #10 · answered by Anonymous · 0⤊ 0⤋