English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The problem is that BC:AC:AB is 3:4:5 and then there's a triangle with sides BC=6 AC=x and AB=x+2. I get it when the ratio applies to the angles but I can't figure out how to do it with the sides and the book doesn't have an example for something like it. I don't want just an answer, I need to know HOW to do it more than I need to know the answer.

2007-02-14 10:53:42 · 3 answers · asked by NeRdYkId1101 3 in Education & Reference Homework Help

3 answers

in ratios
BC=3
AC=4
AB=5
in size
BC=6
just from that you can work out that 6=2*the ratio of 3
therefore AC=8 and AB=10.
so x=8

2007-02-14 10:59:41 · answer #1 · answered by adriantheace 4 · 0 0

BC:AC:AB = 3:4:5
you know BC=6 so AC=4*2 (since 3*2=6) = 8
AB=x+2 or 8+2 = 10

so the ratio holds true: 6:8:10 reduces to 3:4:5

2007-02-14 18:59:53 · answer #2 · answered by Na Pomoč 3 · 0 0

this is the best tip you will have in 'ratios'

in any ratio and proportion, it is best to equate similar figures while leaving one variable as unknown, this way you can immediately get the value of the variable

for example; you have the value BC & AC
ok
lets use these values and equate them with the ratio values
written like this:

BC(ratio) / BC(problem) = AC(ratio) / AC(problem)
3 / 4 = 6 / x
x = 6(4) / 3
x = 8
therefore AC is 8
so AB is x +2 which is 10

very simple

solving ratios this way can make you solve any ratio in the future

always remember to equate similar values or terms either exact number or expressed as variables

try more of it

2007-02-14 19:26:19 · answer #3 · answered by ramel pogi 3 · 0 0

fedest.com, questions and answers