A steel block has a volume of 0.08 m3 and a density of 7,840 kg/m3. what is the force of gravity acting on the block (the weight) in water ?
A. 5,362.56 N
B. 6,150.64 N
C. 6,700.56 N
D. 7,600.18 N
2007-02-14 07:50:49 · 2 answers · asked by Mz. Angel 3y3z 1 in Science & Mathematics ➔ Other - Science
DO YOUR OWN HOMEWORK !!!!!
2007-02-14 07:55:36 · answer #1 · answered by tire chick 4 · 0⤊ 1⤋
Well, I forget what the buoyancy of water is, but you can figure the force of the object without the water, and then subtract the buoyant force of the water upward on the object:
F = 0.08m³ * (7840kg/m³) * (9.8m/sec²) = 6146.56 kg-m/sec²
The upward force of the water would be based on the 0.08m³ displacement. Is there anywhere that you can look that up? Once you have that, you can subtract it from the value above, and you have your answer.
Just as a guess, I'd say A. :-) (because it's less than the value above.
2007-02-14 15:59:26 · answer #2 · answered by Dave 6 · 0⤊ 0⤋