A rock is thrown horizontally at 15 m/s from the top of a cliff. If it takes the rock 4 seconds to hit the ground below, how far from the base of the cliff will the rock have traveled?
2007-02-14 02:04:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
as t = 4sec
acc to equation of projectile
t^2=2h/g
16=2h/10
160=2h
h=80
as height of cliff is 80 m
then horizontal range R=u x 2h/g(under the root)
u=15
R=15 x 4
R=60m
it travel 60 m before landing on the ground
2007-02-14 03:39:36 · answer #1 · answered by Anonymous · 0⤊ 1⤋
As long as all forces are constant and you are in a vacuum etc it will have travelled for 4 seconds and therefore 60m.
2007-02-14 10:14:12 · answer #2 · answered by clever investor 3 · 1⤊ 0⤋
s = ut + 1/2 a t^2
s = 0 + 1/2 x 9.81 x 4^2
s= 78.48 metres
2007-02-14 10:13:37 · answer #3 · answered by Doctor Q 6 · 0⤊ 1⤋