A pressurized can of whipping cream has an internal pressure of 1.05 atm at 25.0 oC. If it is placed in a free

Question

A pressurized can of whipping cream has an internal pressure of 1.05 atm at 25.0 oC. If it is placed in a freezer at -15.0 oC, what is the new value for its internal pressure (in atm)?

Answer 1

assuming ideality. PV = nRT

n and R are constant so

P1V1 = nRT1
P2V2 = nRT2

and V1 = V2

so that P1V1/P2V2 = T1/T2
and P1/P2 = T1/T2

P1 = 1.05 atm
T1 = 25.0 °C
T2 = -15.0 °C

find P2

can you do the rest?