solve the system by the substitution method if there is no solution or an infinite # of solutions, so state?

Question

7x - 4y = 26
y= x - 5

Answer 1

substitue y= x-5 in 1st eq
7x - 4 (x-5) = 26
7x - 4x +20=26
3x=26-20
3x=6
x=6/3
x=2
sub x=2 in 2nd eq or 1st eq whichever u feel easy.
y=x-5
y=2-5
y=-3
if u want check whether the values satisfy the eq.
7(2)-4(-3)=14+12=26
therefore the eqs are satisfied

Answer 2

7x = 4y = 26- - - - - Equation 1
y =x - 5- - - - - - - - Equation 2
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Substitute Method

Insert the y value of equation 2 into equation 1

7x - 4y = 26

7x - 4(x - 5) = 26

7x - 4x + 20 = 26

3x + 20 = 26

3x + 20 - 20 = 26 - 20

3x = 6

3x / 3 = 6 / 3

x = 6 / 3

x = 2

The answer is x - 2

Insert the x value into equation 2

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y = x - 5

y = x - 5

y = - 3

The answer is y = - 3

Insert the y value into equation 2

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Check for eqution 2

y = x - 5

- 3 = 2 - 5

- 3 = - 3

- - - - - - - - -

Check for equation 1

7x - 4y = 26

7(2) - 4(- 3) = 26

14 - (- 12) = 26

14 + 12 = 26

26 = 26

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The solution set { 2, - 3 }

- - - - - - - -s-

Answer 3

By manipulating the first equation:
y = -26/4 + 7/4 x

Substitute that into the second:
-26/4 + 7/4 x = x - 5

Rearrange to isolate x:
x = 4/3(-5 + 26/4) = 2

All you have to do is change one of the equations so that it is in the form y = ......, or x = ......, then put that into the second equation where y or x is.

Answer 4

My answer to this problem is 15.3 with the 3 repeating. If this ir right please tell me so. If not, explain to me how to do it right. I'm an eigth grader, taking Algebra 1, and we just learned this and i'm having trouble

Answer 5

7x-4y=26
y=x-5

7x-4x+20=26
3x=6
x=2
y=-3

Answer 6

more homework issues huh