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For the vertical asymptotes, we don't really care about the limit as x goes to infinity; we're more interested in the values of x for which the denominator is zero. In this case, x=2 or x=-2. The function is undefined outside those two vertical asymptotes, as we would be taking the square root of a negative downstairs. As x approaches either number from the inside (meaning, approach 2 from the left or -2 from the right), y approaches infinity. The function rises without bound.

2007-02-13 19:57:37 · answer #1 · answered by Doc B 6 · 0 0

Asymtote go to infinity, yes.

2007-02-13 19:28:45 · answer #2 · answered by Orion Quest 6 · 0 0

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