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Will the energy of K shell < L shell because it is further away from the nucleus, and thus requires more energy to keep it attracted?

or does K shell have more energy than L shell?

I'm a little confused

2007-02-13 18:58:59 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

The closer to the nucleus, the lower the energy. It doesn't require energy to stay attracted - it requires energy to pull it away.

2007-02-13 19:49:58 · answer #1 · answered by Gervald F 7 · 0 0

The electrons in K shell have less energy then in L shell. As you move further away from the nucleus the energy of electrons in shell increases. That is why you need energy to excite an electron to next energy level.
Sorry, But I can provide you the formula of energy of electron in given shell for only hydrogen atom;-
E=-m(e^4)/[(8ε^2)*(n^2)*(h^2)]
Where
m;-Mass of electron(9.1*10^-31)
e;-Charge on elecron(1.6*10^-19)
ε;-Permittivity of free space(8.85*10^-12)
n:-Principle quantum number(ie;- shell number 1,2,3...)
h;-Planck's Constant(6.63*10^-34)
Notuce that energy is negative as electron is bound to nucleus and as 'n' increases the energy also goes on increasing.

2007-02-14 03:57:42 · answer #2 · answered by Tariq M 3 · 0 0

K electrons are closer to the nucleus than L's, so are at a higher energy level.

2007-02-14 03:46:31 · answer #3 · answered by Anonymous · 0 1

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