If a 5 N force were applied to the person on a car, but no movement resulted, how would you explain this phenomenon?
2007-02-13 17:55:06 · 4 answers · asked by Johnnyboy 2 in Science & Mathematics ➔ Physics
the horizantal friction force=or< Z * R
where 'Z' is a constant between 0 and 1,
and 'R' is the normal reaction..
when the system is resolved upwards the normal reaction will be equal to the weight of the body.
R=mg
so the friction force will defineatly be a greater value than 5N (coz ther would be a higher mass) .therfore the partical may not have a resultant movement..
ya this it, hope u got it clear....
2007-02-13 18:24:57 · answer #1 · answered by thomazzz 1 · 0⤊ 0⤋
The 5 n force was not that heavy to make any movement at all.
2007-02-14 02:02:23 · answer #2 · answered by Geeeenvi V 2 · 0⤊ 1⤋
5N force is not enough to overcome the static friction b/w the car and the ground.
the magnitude of static friction varies from 0-uN.
where 'u' is the coeffiecient of static friction and 'N' normal force
if the magnitude of the applied force exceeds the max. limit the motion starts.
2007-02-14 02:11:33 · answer #3 · answered by juno 2 · 0⤊ 0⤋
Obviously, there is a counteracting force.
You're sitting in your chair, experiencing about 490 N of force from gravity, yet, you don't move downward.
2007-02-14 02:05:31 · answer #4 · answered by arbiter007 6 · 1⤊ 0⤋