How do I find the x-intercepts of the graph: y=2x^2+13x-7 ?

Answer 1

set y = 0, solve for x:

y = 2x² + 13x - 7 = 0;

use quadratic formula to find that
x = { -13 ± √( 169 + 56 ) } ÷ 4 = 0.5 or -7,
so the x-intercepts of the graph are at (.5, 0), and (-7, 0).

Answer 2

when the parabola(since eqn is quadratic) intersects the x-axis, the y ordinate is 0. therefore set 2x^2 + 13x - 7 = 0, which when solved give x = 1/2 and -7. therfore points are (1/2, 0) and (-7, 0)

Answer 3

That is the answer of the formula when y=0
answer

13 + sqrt((13^2) - (4*2*-7) )
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2*2

and

13 - sqrt( (13^2) - (4*2*-7) )
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2*2



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