2x+7=115
x=54 for Melinda
x+7=61 for Mark
2007-02-13 17:01:01
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answer #1
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answered by Jimmy J 2
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I will refer mark as M and Milinda as L
Thus M+ L= 115 ---- (1)
and M= L+7 ---(2)
Put (2) in (1)
--> L+7+L=115
which gives L=54
Put this is (2) --> M=61
Thus mark has 61 caps and Melinda has 54
2007-02-13 17:02:57
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answer #2
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answered by TechMBA 2
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Melinda has n caps.
Mark has n + 7 caps.
n + (n+7) = 115
2n + 7 = 115
2n = 108
n = 54 = Melinda's caps
54 + 7 = 61 = Mark's caps
Check:
61 + 54 = 115
2007-02-13 17:04:50
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answer #3
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answered by ecolink 7
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we say melinda has x caps so Mark has x+7. Then we have the equation.
x+x+7=115
2x+7=115
2x=108
x=54
Mark has x+7 so mark has 54+7=61
Mark 61 Melinda has 54
2007-02-13 17:04:28
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answer #4
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answered by PhyzicsOfHockey 2
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(x+7)+y=115, subtract the 7 from 115 divide that by two, and it comes to xy=54, so melinda has 54 and Mark as 61
2007-02-13 17:02:50
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answer #5
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answered by iammindfreak 3
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mark=x
melinda=y
x+y=115
x-y=7 add
2x=122
x=61
61+y=115
y=54
Mark has 61 caps
Melinda has 54 caps
2007-02-13 17:19:38
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answer #6
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answered by yupchagee 7
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melinda has 54, mark has 61
x+x+7=115
2x+7=115
2x=108
x=54
2007-02-13 17:03:03
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answer #7
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answered by fernjj2 2
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(7+x)+x=115
2x=115-7
2x=108
x=108/2
x=54
2007-02-13 18:43:36
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answer #8
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answered by Helper X 2
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the answer is 61 if it isn't I'm sorry
2007-02-13 20:42:41
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answer #9
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answered by Anonymous
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