2007-02-13 16:51:03 · 4 answers · asked by Selena Q 1 in Science & Mathematics ➔ Earth Sciences & Geology
A = (22/7)r² ----> A/(22/7) = r² ----> 7A/22 = r² ---->√(7A/22) = r.
Given A = 154 sq ft, just plug this value into the area formula and solve for r:
√(7*154/22) = r
√(1078/22) = r
√49 = r
7 = r
2007-02-13 17:01:06 · answer #1 · answered by MathBioMajor 7 · 0⤊ 0⤋
Given: A = (22/7) r^2
A = 154 sq. ft
Solution:
To remove the fraction on the right side, multiply both side of the equation by 7.
7(A) = 22r^2
Substitute the value of A
7(154 sq. ft) = 22r^2
1078sq.ft = 22r^2
Divide both sides by 22
49 sq. ft = r^2
To get r, get the square root of 49.
The value of r is 7 feet.
2007-02-14 06:03:55 · answer #2 · answered by Sparkling Soda 2 · 0⤊ 0⤋
since A=(22/7)r^2
therefore, 154=(22/7)r^2...........................(1)
here, r= radius of the pool
so, from (1) we get,
r^2=154*7/22
or r^2=49
now by taking square root of both L.H.S and R.H.S we get,
r=7
therefore the radius of pool is 7 feet.
2007-02-14 01:05:17 · answer #3 · answered by neha 1 · 0⤊ 0⤋
wow thats hard
2007-02-16 14:10:04 · answer #4 · answered by donielle 7 · 0⤊ 0⤋