College Algebra Help!!!?

Question

1) In the morning, May drove to an important at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1\5 (1 over 5) hour longer. How did she travel to the appointment?

Solve using the quadratic formula.

2) 35x^ + 98x + 40=0

Solve the equation.

3) 4 radical of x= radical of 9x+9

4) radical of x + 6 + the raidcal of 2-x = 4


Thanks

Answer 1

1.) The question makes no sense...

2.) Quadratic formula = (-b +/- ((b^2 - 4ac)^1/2)) / 2a
(-98 +/- ((9604 - 5600)^1/2) / 70
-1.4 +/- (63.277) / 70
-1.4 +/- 0.904
-2.304, -.496

For 3 and 4, when asking questions of these things, use parenthesis to make it clear what's under the radical...
3.) 4√x = √(9x + 9)
Square both sides:
4√x * 4√x = √(9x + 9) * √(9x + 9)
16x = 9x + 9
7x = 9
x = 9/7

4.) √(x + 6) + √(2 - x) = 4

Square both sides:
(x + 6) + 2(√(x + 6)√(2 - x)) + (2 - x) = 16
8 + 2(√(x + 6)√(2 - x)) = 16
2(√(x + 6)√(2 - x)) = 8
(√(x + 6)√(2 - x)) = 4

Simplify:
(√(x + 6)(2 - x)) = 4
(√(2x + 12 - x^2 - 6x)) = 4
(√(- x^2 - 4x + 12)) = 4

Square both sides again:
- x^2 - 4x + 12 = 16
- x^2 - 4x - 4 = 0

Multiply by -1:
x^2 + 4x + 4 = 0
(x + 2)^2 = 0
x + 2 = 0
x = -2 (solution!)

Check:
√(x + 6) + √(2 - x) = 4
√(-2 + 6) + √(2 - -2) = 4
√4 + √4 = 4
2 + 2 = 4 (Check!)