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2007-02-13 09:02:08 · 5 answers · asked by jmartinme 2 in Science & Mathematics Biology

5 answers

The code is the series of nitrogen bases.
The sugars (deoxyribose) and phosphates form the sides of the DNA "ladder", but they don't have anything to do with the code. They are the same for every nucleotide.

2007-02-13 09:22:09 · answer #1 · answered by ecolink 7 · 0 0

Partly.

DNA stands for deoxyribose nucleic acid.

You see the word 'ribose' amongst this? Ribose is the name given to a sugar molecule with 5 carbon atoms. So yes a DNA strand does have a long line of sugars attached together. However there are other things present (as seen from the name). The most obvious one is nucleic acids.

In fact a length of single stranded DNA is comprised of a length of parallel nucleotides (the nucleic acids) linked by a 'backbone' of alternating phosphate groups and ribose sugars.

So sugar is just one of the 3 key components to form a DNA strand.
1) Sugar
2) Phosphate group
3) nucleotide

However the sugar plays NO part in the DNA 'code'. The code is held in the nucleotides.

When two DNA strands join (double helix) nucleotides from both sides meet forming pairs. It is these nucleotide base pairs that form the genetic code.

2007-02-13 09:12:37 · answer #2 · answered by riverdrudge 2 · 1 0

are you talking about codons? then it's nitrogen bases...deoxyribose sugar makes up the backbone, along with the phosphate group
wikipedia: DNA is a long polymer of simple units called nucleotides, which are held together by a backbone made of sugars and phosphate groups. This backbone carries four types of molecules called bases, and it is the sequence of these four bases that encodes information. The major function of DNA is to encode the sequence of amino acid residues in proteins, using the genetic code.

2007-02-13 09:08:08 · answer #3 · answered by bksrbttr 3 · 1 0

Ribose is a sugar!
like glucOSE
and dextrOSE
and surcrOSE

2007-02-13 09:08:40 · answer #4 · answered by Anonymous · 0 0

Yes, DEOXYRIBOSE

2007-02-13 09:05:11 · answer #5 · answered by Anonymous · 1 0

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