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(-2/5, 2/5) and (4/3, 2/3)

I'm supposed to find an equation of the line, but once I find the slope I know how to put the information into point-slope form. The issue i'm having is that I've never put found the change in y minus the change in x when x and y are fractions. In fact i've never divided fractions containing fractions before so i'm pretty confused with this...any explaination or illustration on finding the slope would be appreciated. Thanks.

(-2/5, 2/5) and (4/3, 2/3)

2007-02-13 08:43:47 · 2 answers · asked by World Expert 1 in Education & Reference Homework Help

2 answers

use formula of slope
if a line passing through points (x1,y1) and (x2,y2 ) then slope of line is
m = y2- y1 / ( x2 - x 1)
here
x1 = -2/5 y1 = 2/5
x2 = 4/3 y2 = 2/3

plug in the values in the formula and solve to get the slope
we get m = 2/13

use POINT SLOPE FORM OF LINE ...to get the equation of line
y - y 1 = m (x - x1)

Hope this will help you

2007-02-13 09:00:59 · answer #1 · answered by RAKESHtutor 3 · 0 0

If I remember correctly to divide a fraction you need to multiply by the reciprocal. So it would be -2/5*5/2 and 4/3*3/2. -10/10 = -1 and 12/6 = 2. But I'm not sure about that.

2007-02-13 08:53:34 · answer #2 · answered by SinX 1 · 0 0

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