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The speed of light is 3.0×108 m/s and the speed of sound is 3.4×102 m/s. Find the value of the integer 'n' in the following statement:
If you start counting seconds when you see something happen and stop when you hear it happen, for every 'n' seconds counted the event was about 1km away.

2007-02-13 08:39:07 · 3 answers · asked by avemaria 2 in Science & Mathematics Physics

3 answers

In 1 second, sound travels 340 m.
In 2 seconds, sound travels 680 m.
In 3 seconds, sound travels 1020 m.

So, if you see something happen far away, and can count 3 seconds before you hear it, it is about 1 km distant.

2007-02-13 10:05:12 · answer #1 · answered by Thomas G 3 · 0 0

You should remember that Distance = Velocity x time

Therefore, for the speed of light travelling (we'll say1 km) it takes-:

1000m = 3 x 10^8 x time

1000m / 3 x 10^8 = 3.33333 x 10^-6 seconds
(i.e. you wouldn't notice this time period)

For sound to cover this distance -:

Distance = Velocity x time

1000m = 340 x time

1000 / 340 = 2.9412 seconds.

If you subtract the lights time from the sounds time-:

2.9412 - 3.3333 x 10^-6 = 2.9411966667 seconds
(i.e. the time difference between the two events per Kilometre.)

Sound is nowhere near as fast as light. The bigger the distance, the more you would notice the time difference between the 2 by this amount per Km.

2007-02-13 09:07:53 · answer #2 · answered by Doctor Q 6 · 0 0

Speed of light=3.0x10^8m/s
Speed of sound=3.4x10^2m/s

We assume seeing something is instantaneous, in other words, no time passed
Distance=rate x time
D=(3.4x10^2 ) x n
If D=1000meters
1000=3.4x10^2 x n
n=1000/3.4x10^2
n=3 sec

2007-02-13 09:13:25 · answer #3 · answered by science teacher 7 · 0 0

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