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A steel ball rolls down a ramp (like a "ski jump") and leaves the ramp in the horizontal direction. You measure the speed of the ball with a photogate and a timer (your computer). The computer records the time the light beam of the photo gate is blocked by the ball, when moving through the gate. The recorded time is 6.94ms (NOTE ms = mili second). What is the speed of the ball if the width of the ball blocking the light beam is 1.002cm ?

The answer is 1.443804, but how do u do it?

2007-02-13 05:26:30 · 3 answers · asked by Paul S 2 in Science & Mathematics Physics

3 answers

it travels 1.002cm in 6.94ms
so, in meters per second,
the velocity would be the distance traveled over the time it takes.
since acceleration is zero because it is moving horizontally.

1.002cm * 1m/100cm *1/6.94ms * 1000ms/s = 1.443804m/s

2007-02-13 05:36:15 · answer #1 · answered by Michael Dino C 4 · 0 0

Distance (ball moves through photogate) = rate (speed of ball) x time (it takes to move through photogate)

r (m/s) = 0.01002 m / 0.00694 s = 1.443804 meters per second

2007-02-13 13:38:16 · answer #2 · answered by hevans1944 5 · 0 0

The diameter of the ball is 1.002cm so it will travel a distance of 1.002 cm while it blocks the infrared signal. It takes 6.94 ms to travel this distance. Since rate = distanve divided by time we have rate = 1.002/6.94 = 0.1443804 cm/ms.

To get your answer, we need to hange cm to mm so answer would be 1.443804 mm/ms, or 1.443804 meter/second
mm/ms = millimeters/millisecond

2007-02-13 14:04:00 · answer #3 · answered by ironduke8159 7 · 0 0

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