Algebra 2....?

Question

3: Savannah left Miami and drove at a speed of 47 mph. Timothy left 2 hours later and drove at a speed of 58 mph. How long will it take Timothy to catch up with Savannah?
Hint: since they both go the same distance, we can set their distance expressions equal for the equation.





8.55 hours
10.55 hours
7.5 hours


4: Two jets leave an airport at the same time in opposite directions. The first jet is traveling at three hundred twenty-three mph and the other at two hundred mph. How long will it take for the jets to be 2,371 miles apart?
Hint: you are given a total distance. Therefore, jet 1's distance expression plus jet 2's distance expression equals the total distance.





4.53 hours
2.37 hours
123 hours


5: Caleb left New York and drove at a speed of 15 kph. Ryan left 3 hours later and drove at a speed of 20 kph. How long will it take Ryan to catch up with Caleb? ?
Hint: since they both go the same distance, we can set their distance expressions equal for the equation.





12 hours
9 hours
6 hours


6: Alexander left Miami and drove at a speed of 46 mph. Thomas left 1 hour later and drove at a speed of 60 mph. How long will it take Thomas to catch up with Alexander?
Hint: since they both go the same distance, we can set their distance expressions equal for the equation.





4.29 hours
3.29 hours
5.29 hours

Answer 1

These are all VERY similar....

3: Savannah left Miami and drove at a speed of 47 mph. Timothy left 2 hours later and drove at a speed of 58 mph. How long will it take Timothy to catch up with Savannah?
Hint: since they both go the same distance, we can set their distance expressions equal for the equation.





8.55 hours
10.55 hours
7.5 hours

D=RT
Savannah's time = T
Timothy's time = T+2
47T = (T-2)58
47T = 58T - 116
-11T = -116
T = -116/-11 = 10 6/11 hours or 10.55 hours



4: Two jets leave an airport at the same time in opposite directions. The first jet is traveling at three hundred twenty-three mph and the other at two hundred mph. How long will it take for the jets to be 2,371 miles apart?
Hint: you are given a total distance. Therefore, jet 1's distance expression plus jet 2's distance expression equals the total distance.





4.53 hours
2.37 hours
123 hours


D=RT ---> D/R = T OR T = D/R
Time is the same for both.
Let D = jet one's distance
Plug in what we know & solve.
D/323 = (2,371 - D) / 200
MUltiply the numbers out of the demoninator...
200 D = 323 (2,371 - D)
200 D = 765,833 - 323 D (Add 323 D to both sides.)
523 D = 765,833 (Divide both sides by 523.)
D = 1464 (plug this back into the equation for Jet one's Time)
T = 1464/323 = 4.53 hours


5: Caleb left New York and drove at a speed of 15 kph. Ryan left 3 hours later and drove at a speed of 20 kph. How long will it take Ryan to catch up with Caleb? ?
Hint: since they both go the same distance, we can set their distance expressions equal for the equation.





12 hours
9 hours
6 hours

Let t = Caleb's time
15t = 20(t - 3)
15t = 20t - 60
-5t = -60
t = 12 hours


6: Alexander left Miami and drove at a speed of 46 mph. Thomas left 1 hour later and drove at a speed of 60 mph. How long will it take Thomas to catch up with Alexander?
Hint: since they both go the same distance, we can set their distance expressions equal for the equation.





4.29 hours
3.29 hours
5.29 hours


Let Alexander's time = t
46t = 60 (t - 1)
46t = 60t - 60
-14t = -60
t = 4.2857 = 4.29 hours