A 5.888 kg block slides with constant velocity on a horizontal plane. The coefficient of friction is 0.35. The block is pushed by a force which is parallel to the plane. How large is this force ? Indicate with a negative (positive) sign whether the direction of this force can (cannot) be obtained from the direction in which the block is sliding.
The answer is 20.216448, but how do u get it?
2007-02-13 02:06:34 · 3 answers · asked by Paul S 2 in Science & Mathematics ➔ Physics
Weight of Block x Gravity = Normal Reaction from Table
5.888 x 9.81 = 57.76 Newtons.
57.76 x 0.35 = 20.216448
Friction always acts in the opposing direction to the motion.
2007-02-13 02:29:01 · answer #1 · answered by Doctor Q 6 · 0⤊ 0⤋
Since the body moves with constant velocity,
the frictional force must be equal but opposite to the applied force.
The frictional force = - μ m g = 0.35 x 5.888 x 9.81
= - 20.216448 N.
Negative sign, as this force is opposite to the direction of motion or force.
2007-02-13 10:24:38 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
technique but no answer:
1) resolve forces vertically - find R (normal reaction)
2) use F=uR to find the frictional force
3) equation of motion hoizontally (note that a=0 as it is constant velocity)
4) yes it can be obtained in the sliding direction.
2007-02-13 10:13:02 · answer #3 · answered by aeronic 2 · 0⤊ 0⤋