{(d+3)/(8d)} - {(2d+1)/10d^2)} =
(___^2 + ___)/(___^2)
Sorry, I posted this, but I had the formula wrong, thanks!
2007-02-13 01:48:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Ok, so the commond denominator could be 40d^2
So the numerator is:
(d+3)(5d) - (2d+1)(4)
= 5d^2 + 15d - 8d - 4
= 5d^2 + 7d - 4
That doesn't factor, so your final answer is:
5d^2 + 7d - 4
----------------
40d^2
2007-02-13 02:00:50 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
r u shure u got the question right?
cause for the question u hae given the answer is =(5d^2 + 7d - 4)/40d^2
2007-02-13 10:50:14 · answer #2 · answered by absentmindednik 3 · 0⤊ 0⤋
Look, if you're expecting us to do your homework for you, the least you can do is get the formula right. Now I've got to start my calculations all over.
2007-02-13 09:52:20 · answer #3 · answered by §Sally§ 5 · 0⤊ 1⤋