2x^2=56.............................please help asap?

Answer 1

2x^2=56
x^2=28
x=2.under root(7)

Answer 2

x^2 = 56/2
x^2 = 28
x = 28^1/2
(x = the square root of 28)

Answer 3

I assume your solving for "x", correct?

2x^2 = 56

First: isolate "x^2" on one side --- divide both terms by "2" (when you move a term to the opposite side, always use the opposite sign).....

(2x^2)/2 = 56/2

*Cross cancel "like" terms & combine the remaining terms...

x^2 = 56/2

x^2 = 28

Sec: eliminate the exponent - find the square root of both sides....

V`x^2 = +/- V`28

V`x*x = +/- V`28

x = +/- V`28

Third: express "28" in lowest terms...

x = +/- V`4*7

x = +/- V`2*2*7

*Finding the square root means - when you have a pair of the same number or, when you have a number in the radical sign repeated twice > write the number in front of the radical sign.

x = +/- 2 V`7

Or, x = - 2 V`7 & 2 V`7

Answer 4

2x² = 56

2x² / 2 = 56/ 2

x² = 28

√x² = √28

√x² = √4√7

x = ± 2 √7

- - - - - - - -s-

Answer 5

2x^2 = 56 (Divide both sides by 2)
x^2 = 28 (Take square root from both sides)
x = sqrt 28 or 2 * sqrt 7

Answer 6

2x^2 = 4x

4x = 56 (Divide both sides by 4)

x = 14

or it could be-:

(2x^2) = 56

x^2 = 56/2
x^2 = 28
x = 5.29

It depends if it has any brackets on the function

Answer 7

2x^2 = 56
x^2 = 28
x = square root of 28

Answer 8

2x^2=56
ANS:

X^2= 56/2
X= square root of 28
x=+/- 2 ( square root of 7)

Answer 9

2x^2 = 56

Divide both sides by 2,

x^2 = 28

Take the square root of both sides.

x = +/- sqrt(28)

But sqrt(28) can be reduced to 2sqrt(7), so

x = +/- 2sqrt(7)

Answer 10

not clear what you want.
if you want to find x then there are 2 possible solutions to this quadratic equation
x = sqrt(28) or x = -sqrt(28)