Help W/ Math????

Question

axis of symmetry and roots of equation of x^2+5x-6?

Answer 1

Ok. The equation of a parabola (the one you have is a parabola) is ax+by+c. My math teacher doesn't know who invented this, but the equation of the axis of symmetry is always -b/2a. So what you have to do is take the numbers of your equation and plug them into that equation.

To find the roots of an equation, what you have to do is factor your equation. How you do that is you break up X^2+5X-6 into four terms, instead of 3 like you have. To do this, you need to find 2 numbers whose PRODUCT is -6 and whose SUM is 5 (from the 5X). Once you find these numbers, you put them into the equation in X form.

An example of this would be X^2+2x-3. I would have to find 2 numbers whose PRODUCT is -3 and whose SUM is 2. Those numbers are 3 and -1. So I plug those in as X's. The new equation would be X^2-1x+3x-3. Now you have four terms and when you have four terms you break it up to factor it. You can break it up like this (x^2-1x) + (3x-3). Then you factor it. So it would look like this: x(x-1) + 3(x-1). Since the binomials in the parentheses are the same, the equation would now look like this (x-1) * (x+3)...the x+3 was from the outside numbers of the parentheses...you put those into binomial form too!

Then you set x-1=0 and also x+3=0 and solve for x. The solutions would be 1 and -3. Now plug those into the original equation and they work!

All you have to do is follow those steps for your equation! Hope this helps.

Answer 2

X^2+5x-6 = 0
X^2 + 3x -2x -6=0
(x+3)(x-2)=0
Roots are x= - 3,2

Axis of Symmetry is 6.

Answer 3

(x+6)(x-1)
x=-6,1
axis of symmetry is -6