Solve this equation and show steps and work plz.?

Question

w+3 = 2/3 (w+7)

Answer 1

Solve "w" in w + 3 = (2/3)(w + 7)

First: eliminate parenthesis --- distribute the outer term with the terms in parenthesis....

w + 3 = (2/3)(w) + (2/3)(7)

w + 3 = 2w/3 + (2*7)/3

w + 3 = 2w/3 + 14/3

Sec: eliminate fractions --- multiply the denominator with each term....

(3)(w) + (3)(3) = (3)(2w/3) + (3)(14/3)

*Cross cancel "like" terms & combine the remaining terms....

(3)(w) + (3)(3) = 2w + 14

3w + 9 = 2w + 14

Third: combine "like" terms - subtract 9 from both sides (when you move a term to the opposite side, always use the opposite sign)....

3w + 9 - 9 = 2w + 14 - 9

3w = 2w + 14 - 9

3w = 2w + 5

*Subtract 2w from both sides....

3w - 2w = 2w - 2w + 5

3w - 2w = 5

w = 5

Answer 2

This is a simple re-arrangement-:

w + 3 = 2/3 (w + 7)

Multiply both sides by 3-:

3 (w + 3) = 2 (w + 7)

Now multiply out brackets-:

3 w + 9 = 2w + 14

Subtract 9 from both sides-:

3w = 2w + 5

subtact 2w from both sides-:

w = 5

You really need to practice equations like this, as they are very common at GCSE level maths.

Answer 3

W+3 = 2/3(W+7)
3(W+3) = 2(W+7)
3W +9 = 2W+14
3W-2W = 14-9
W = 5

Answer 4

to solve these qtn types,rearange the eqn
w+3=2(w+7)/3.
bcos 3 is dividing, it will cross the equal sign to the other side to multiply to get a linear eqn
3(w+3)=2(w+7)

3w+9=2w+14 ,opening the brackets
3w-2w=14-9 ,
groupn liked terms(2w crosses equal sign to the left and bcoms negative, while 9 crosses equal sign to the right and also negates.)

1w=5 , simplifying

bcos 1w is written as w, the answer is

w=5.

hope u have understood.

Answer 5

w+3 = 2/3 (w+7)
w+3 = (2w+14)/3
3(w+3) = 2w+14
3w+9 = 2w+14
3w-2w = 14-9
w = 5