2x+y-4=0...please answer..?

Question

instructions: GRAPH THE FOLLOWING FUNCTIONS BY POINT-PLOTTING...

there are 2 questions:

1. 2x + y - 4 = 0
2. 3x + 5y = 6



thank you...^_^

Answer 1

Put you equations into the form y = mX + C
where y is your plot point on the Y axis when X = 0 and X is your plot point on the X axis when Y = 0

Here is the first one:

y = -2X + 4

so when X = 0 you can see that y = 4
and when y = 0 you can see that X = 2

So there are your main plot points. Try a couple of other values for X to plot some more points and then join up the plot points to draw your graph.

Do the same for the other equation to draw it's graph.

Answer 2

when plottn a linear graph,you will need 2 pts on each line.
for the first eqn,
2x+y-4=0
for x pt, let y=0
2x+0-4=0
2x-4=0
2x=4 , -4 crosses equal sign n bcoms positive
x=4/2
x=2.

there4, when y pt is 0, x=4
this is one pt (4,0). plot dis pt on the graph.draw a line thru the pts plotted. ie(4,0)


taking the second eqn,with the same steps,
we put y=0

3x+5(0)=6
3x=6
x=6/3 ,bcos 3 which was multiplying crosses equal sign to divide
x=2

therefore, when y=0, x=2
this is another pt (2,0). then plot on the graph.draw a line thru the pt.i.e.(2,0)

all the best...

Answer 3

first, find the x and y intercepts for both equations. To find the x intercept, equate y to 0. Do the same to get the y int. After that, plot the points of each and make two intersecting lines. Find the common point of intersection and that will be the answer.

Answer 4

y = 4 - 2x
y = (6 - 3x)/5

y is a complex little bugger. probably works for intelligence.