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By what factors must you multiply the volume of a gas measured at 20 'C and 750mm Hg in order to find what the volume would be at s.t.p ( standard temperature and pressure)??

2007-02-12 22:24:17 · 2 answers · asked by iqnabeel 1 in Science & Mathematics Chemistry

2 answers

You know the ideal gas law: PV= nRT
so at stp PoVo= nRTo
and at 20 C P1V1= nRT1

It is the same quantity of gas thus the number of mole (n) is the same. Divide the two equations and you get
PoVo / (P1V1)= To/T1 =>
Vo= P1V1*To/ (T1*Po) = [(P1/Po)*(To/T1)] * V1

so the factor is [(P1/Po)*(To/T1)]
at stp To=273 K and Po= 760 mm Hg

so you have (750/760)*(273/298) =0.904

2007-02-13 09:13:03 · answer #1 · answered by bellerophon 6 · 0 1

2 points sorry for that

2007-02-13 06:42:43 · answer #2 · answered by Anonymous · 0 1

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