At an automotive repair shop 50 cars were imspected.Suppose that 23 cars needed new brakes and 34 cars needed new exhaust systems .
a. what is the least # of cars that could have needed both?
b. What is the greatest number of cars that could have needed both ?
c. what is the greatest # of cars that could have needed neither.
Let me know how you determine the answers. I will match with mine :o(
2007-02-12 18:07:49 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
a. Least # of cars that could have needed both.
23 + 34 = 57. There are a total of 50 cars. So, there would be atleast 7 cars that need both
b. Greatest number of cars that needed both.
Maximum would be 23 (least of both). You can't have more than 23 cars because if that is the case you should be having more than 23 for brake failures.
c. Greatest @ of cars that could have needed neither.
Apply the same logic. But here you have to take the greatest of both and minus with the total
50-34 = 16
2007-02-12 18:20:17 · answer #1 · answered by jaggie_c 4 · 2⤊ 0⤋
a. 11 (least - both)
b. 23 (most - both)
c. 16 (most - neither)
it's been awhile since I've had to do this kind of stuff
2007-02-12 18:19:13 · answer #2 · answered by Mystery_Woman 2 · 0⤊ 0⤋
Problem solving: Spelling the word mathematics.
a) 7
b) 23
c) 16
2007-02-12 18:10:29 · answer #3 · answered by Mickey Mouse Spears 7 · 0⤊ 0⤋
Maybe you should show how you solved these questions and the answers you got and folks can help you with alternate or better methods :)
2007-02-12 18:14:21 · answer #4 · answered by pragyana 3 · 0⤊ 0⤋