In a class of 78 students 41 are taking French, 22 are taking German and 9 students are taking both French and German. How many students are not enrolled in either course?
A. 6
B. 15
C. 24
D. 33
E. 54
2007-02-12 18:03:07 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
n = 78 - (41 + 22 - 9)
n = 78 - 54
n = 24
2007-02-12 18:13:39 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
It is a badly worded question. If we assume that 41 are taking French ONLY and 22 are taking German ONLY, then the answer is 6 (78-(41+22+9)). But if we assume that 41 are in the French class and some of those are also in the German class, and 22 are in the German class and some of those are in the French class then the answer is 24 (78-(41+22-9)).
The second interpretation is more likely so the answer is C, but you could argue that the first interpretation is correct, in which case the answer would be A.
2007-02-12 18:14:40 · answer #2 · answered by Zachary F 2 · 0⤊ 0⤋
6
2007-02-12 18:07:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋
15
2007-02-12 18:17:14 · answer #4 · answered by yeng 1 · 0⤊ 0⤋
78-(41+22-9)=24
2007-02-12 18:08:40 · answer #5 · answered by amin s 2 · 0⤊ 0⤋
D. 33
i am arnd for further explanation
2007-02-13 00:44:13 · answer #6 · answered by Prince 1 · 0⤊ 0⤋