Plz anyone tell me the answer i got millions of answers but its all wroong plz helpppp?

Question

If a certain source emits radiation of wavelength 320. nm what is the energy, in kJ, of one mole of photons of this radiation?

Enter a numeric answer only.

Answer 1

Energy / Mode = 43.197 * 10^-25 Kilo-Joules

There is nothing like 1 MOLE of radiation. Here you have mentioned MOLE wrongly. It is basically MODE or Quantum.

It is a question of blackbody radiation, which reradiates energy in monochromatic wavelength (320 nm, > lower wavelengths). So it will qualify Wien’s disp. law for 1 wavelength, and max-Lamda will give us its temperature in 0K.

Classically : There are [8*pie/c*(lamda)^2] modes in one cavity of radiation, all modes possible and each having kT energy per mode (reduced form of Q. Mech term). Quantam Mech : There are [8*pie/c*(lamda)^2] modes in one cavity of radiation, quantized modes with upper modes less likely, and each having

(hc/lamda) [1 / [exp (hc/lamda* kT) –1] energy per mode

(Lamda)max * T = 2.897*10^6 (nm-K) or T= 9053.125 (K)

hc/(Lamda) = 6215.625* 10^-22 Joule, kT = 1248.917*10^-22 (J)

Energy/MODE = (hc/lamda) [1 / [exp (hc/lamda* kT) –1] joules
= 43.197 * 10^-25 Kilo-Joules

Answer 2

37.4079 kJ. [Use E=6.022*10^23 * h*c/wavelength]

Answer 3

6.626E-34 * 2.9979E8 * 6.022E23 / 320E-9
= 373.8 kJ