find the derivitive please!?

0 ⤊

find the derivitive please!?

[4x^2/3x^3]^1/3

2007-02-12 17:10:38 · 2 answers · asked by musical_fish1 1 in Science & Mathematics ➔ Mathematics

2 answers

First simplify the expression. Then take the derivative.

[4x^2/3x^3]^1/3 = [4/(3x)]^(1/3) = (3x/4)^(-1/3)

d{(3x/4)^(-1/3)}/dx = (3)(-1/3)(3x/4)^(-4/3)
= -(3x/4)^(-4/3)

2007-02-12 18:10:49 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋

Begin by simplifying the expression: [4/(3x)]^(1/3)

Then apply the chain rule (take the derivative and then multiply by the derivative of what's inside).

(1/3)[4/(3x)]^(-2/3) * (-12/(9x^2))

Then you just have to simplify things a bit.

2007-02-13 01:27:58 · answer #2 · answered by Milton's Fan 3 · 0⤊ 0⤋