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A certain conductor has 6.50 1028 free electrons per cubic meter, a cross-sectional area of 4.00 10-6 m2, and carries a current of 2.10 A. Find the drift speed of the electrons in the conductor.

2007-02-12 15:40:03 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

I=n A V(drift)
I - current
n - number of free electrons per unit volume in the conductor
A - area of the conductor
V(drift) avg drift speed

V(drift)=I/(n A)
V(d)=2.10 /(6.50 e+28 x 4.00 e-6 )

V(d)=8.07 e-24 m/s
or

V(d)=8.07 10-24 m/s (according to your notation)

2007-02-13 04:28:00 · answer #1 · answered by Edward 7 · 0 0

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