A red number cube and blue number cube are rolled . What's the probability of the red cude showing a 3 and the blue cibe showing a 6 .
2007-02-12 15:33:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
ok. the chances of getting a 3 on a 6 sided cube, numbered 1-6, is 1/6. the chances of getting a 6 on the blue cube is the same, 1/6. the chances of getting both is their product, 1/6 * 1/6 = 1/36
here is a diagram of all the possibilities
R....B
1...1
1...2
1...3
1...4
1...5
1...6
2...1
2...2
2...3
2...4
2...5
2...6
3...1
3...2
3...3
3...4
3...5
3...6<<<<<<<<<<<<<
4...1
4...2
4...3
4...4
4...5
4...6
5...1
5...2
5...3
5...4
5...5
5...6
6...1
6...2
6...3
6...4
6...5
6...6
the chances of getting that one combination is 1/36
2007-02-12 15:37:37 · answer #1 · answered by Ace 4 · 0⤊ 0⤋
Well, the red 3 would be 1/6 and the blue 6 would be 1/6 so you multiply them together and get 1/36 chance of getting that combo.
2007-02-12 23:36:14 · answer #2 · answered by Cathy K 4 · 0⤊ 0⤋
Those are independent events. So it's just 1/6 * 1/6.
2007-02-12 23:38:48 · answer #3 · answered by Curt Monash 7 · 0⤊ 0⤋
1/6 &1/6
2007-02-13 00:01:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Everyone above is correct. The answer is 1/36.
2007-02-12 23:40:24 · answer #5 · answered by math10sprof 2 · 0⤊ 0⤋