i don't know how to solve this problem:
The area of a triangle is 384 cm.sq. Its base is 3 times the height, find the base and the height.
you dont have to do the problem for me but, can you help me go about solving it? thanks SOO much!
2007-02-12 15:20:40 · 5 answers · asked by okay. 2 in Science & Mathematics ➔ Mathematics
I love your attitude!
The area is 1/2 * base * height.
But from the information given, that's just 3/2 * the square of the height!
You can surely take it from there. ;)
Algebraically:
384 = A = 1/2 * B * H
B = 3 * H
384 = 1/2 * 3 * H * H
Simplify and solve.
2007-02-12 15:25:22 · answer #1 · answered by Curt Monash 7 · 0⤊ 0⤋
Assume an identical triangle is adjoined at the hypotenuse. The area of the resulting rectangle (we are assuming right triangles, but the analysis is true generally) will be 768 cm*2. Let the height be h. The base is then 3h, and the area of the figure is 3h^2. This is easily solved to give h = 16.
2007-02-12 15:29:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Area of Triangle = (1/2)*base*height = 384 cm sq.
and you know that base = 3*height
therefore, Area=(1/2)=(3*height)*height=(.5)*4*height=2*h
height = 384/2=192 cm
and
base = 3*h=3*192= 576 cm
2007-02-12 15:23:59 · answer #3 · answered by David T 3 · 0⤊ 0⤋
the formula is A=1/2 bh. substitute in. 384=1/2 (3h)(h)
(384x2)/3=h^2
square root of 256 = 16
so.... h=16, b=48
2007-02-12 15:25:07 · answer #4 · answered by paula s 2 · 0⤊ 0⤋
1/2 b*h=A
A=384 cm sq.
384=1/2 3h* h
2*384=3h^2
h^2=256
h=16 cm
b=48 cm
2007-02-12 15:26:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋