Solve these problems.?

Question

1) x^2+1/x^2-1 = 2/x-1 + x/x+1

2) 1/x-1 + x/3 = x/x-1

1) x^2+1/x^2-1 = 2/x-1 + x/x+1

2) 1/x-1 + x/3 = x/x-1

for number one x^2+1 is over x^2-1 in fraction form and 2 is over x-1 in fraction form and x is over x+1 in fraction form

for number two x is over x-1 in fraction form and x is over 3 in fraction form and x is over x-1 in fraction form

sorry about the confusion =s

Answer 1

I'm not sure how your problem is supposed to be written...

is it x^2 + (1/x^2) - 1 = (2/x) - 1 + (x/x) + 1?

or is it (x^2 + 1)/(x^2-1) = 2/(x+1) + x/(x+1) Note in this case that x cannot be -1 or 1 or the equation would be undefined because of dividing by zero.