What are the boiling point and freezing point of a 3.88 m solution 0f naphthalene in benzene? i?

Question

The boiling point and freezing point of benzene are 80.1°C and 5.5°C, respectively.)
boiling point

Answer 1

You have to apply the formula (delta) Bp = Kb x molality.
The Kb value for benzene is 2.53.
2.53 x 3.88 = 9.82
Bp(solution) = 89.9 C

The freezing point has a similar formula (delta) Fp = Kf x molality
The Kf value for benzene is -5.12
-5.12 x 3.88 =-19.9
Fp (solution) = 5.5 - 19.9= -14.4 C