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(a) 14.2 g of sucrose (C12H22O11) in 686 g of water
m
(b) 7.04 moles of ethylene glycol (C2H6O2) in 3676 g of water
m

2007-02-12 15:16:45 · 1 answers · asked by chance w 1 in Science & Mathematics Chemistry

1 answers

14.2 g/0.686kg x 1 mole/342 = 0.0605m (3 sig figs)

7.04mol/3.676kg = 1.92 m (3 sig figs)

2007-02-12 15:45:45 · answer #1 · answered by docrider28 4 · 0 0

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