A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound of the ball hitting the pins 2.5 s after the ball was released from his hands. What is the speed of he ball? The speed of sound is 340 m/s.
2007-02-12 11:18:27 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Since d = vt, the time it would take sound to go from the pins back to the bowler would be t = d/v.
In this case it would be t = 16.5 m / 340 m/s = .0485 s.
That means the time to get to the pins was 2.5 s minus .0485 s which is 2.451 s.
Finally v = d / t, so the v of the ball is 16.5 m/ 2.451 s which is 6.73 m/s
2007-02-12 11:27:05 · answer #1 · answered by Thomas G 3 · 0⤊ 0⤋
hmm.
speed of ball is v. The time between the release of the ball and the sound of the struck pins is thus 16.5/ v + 16.5/340=2.5 sec.
Solve it. Might work.
When you get this on a test they'll have an extra wall for the sount to bounce off of.
2007-02-12 19:29:29 · answer #2 · answered by 2n2222 6 · 0⤊ 0⤋
let t represent the time the bowling ball to hit the pins. The total time is 2.5s, that means 2.5 - t is the time it takes sound to travel back
x=vt
16.5 = 340(2.5-t)
solve for t
t= 2.4515
x=vt
16.5 = V(2.4515)
V = 6.73m/s
2007-02-12 19:34:42 · answer #3 · answered by 7 · 0⤊ 0⤋