a hardy weinberg question?

Question

a biologist catches 1600 moths using specail inscet traps. of this popluation, 64 exhibit the recessive penontype (bb), and 1536 the dominant phenotype (BB or Bb). assuming that this is a random sample of the wild popluation, is the popluation at genectic equililbrium? explain how you know

Answer 1

q^2 = (64/1600) so q = 0.2

But I don't think you can know if they are at equilibrium with just the information given.

Answer 2

64/1600 = 0.04 = q^2
q = 0.2

p + q = 1
p = 0.8

p^2 + 2pq + q^2 = 1
0.64 +2pq + 0.04 = 1
2pq = 0.32
pq = 0.16

I don't see any problem here.
Unless I am overlooking something, it looks like the Hardy-Weinberg equilibrium applies.