James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28. what are the ages of James and Austin?
tricky! can you figure it out?
2007-02-12 08:28:11 · 5 answers · asked by <3 2 in Education & Reference ➔ Homework Help
1 and 5. 3 times James age is 3, increased by square of Austin's age which is 5^2=25. Add 25 and 3 to get 28.
2007-02-12 08:36:39 · answer #1 · answered by theeconomicsguy 5 · 1⤊ 0⤋
Austin is 5 and James is 1. 5 - 1 = 4 1 x 3 is 3. 5 squared is 25. 25+3 is 28.
2007-02-12 16:34:01 · answer #2 · answered by megastarr92 2 · 0⤊ 2⤋
James is 1.
Austin is 5.
5-4=1
3x1=3+5^2=28
2007-02-12 16:46:55 · answer #3 · answered by Portia 2 · 0⤊ 0⤋
Let A denote Austin's age and J denote James' age.
J = A - 4
3J + A² = 28
3(A - 4) + A² = 28
3A - 12 + A² = 28
A² + 3A - 40 = 0
(A + 8)(A - 5) = 0
The positive answer for A is 5, so, J = 1.
2007-02-12 16:54:01 · answer #4 · answered by S. B. 6 · 0⤊ 0⤋
James is one and Austin is five.
1x3=3
5^2=25
3+25=28
2007-02-12 16:52:54 · answer #5 · answered by red 2 · 0⤊ 0⤋