y^5 divided by y^3 times y^2 =
2007-02-12 05:44:40 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Again, the answer will vary depending on where parentheses are meant to be in your equation. But, if there aren't supposed to be any, then you proceed left to right. when dividing two numbers that have like bases (all three numbers here have like bases...the base is y) then you subtract the exponents. i.e.: y^a/y^b=y^(a-b)
when multiplying, you add the exponents: (y^a)*(y^b)=y^(a+b)
so solve (y^5)/(y^3) and then multiply the answer by y^2
2007-02-12 05:52:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1
2007-02-12 13:49:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
y^2 times y^2 = y^4
2007-02-12 13:48:52 · answer #3 · answered by richardwptljc 6 · 0⤊ 0⤋
y^2(y^5 / y^3) =
y^2(y^2)= y^4
2007-02-12 13:49:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋
This simplifies to 1
2007-02-12 13:48:33 · answer #5 · answered by bequalming 5 · 0⤊ 0⤋
Laws of indices, multypling = add indices, dividing = subtract indices, so the answer is y^(5-3+2) = y^4
2007-02-12 13:54:27 · answer #6 · answered by Anonymous · 0⤊ 0⤋
y^5/(y^3*y^2)=y^5/y^(2+3)
=y^5/y^5
=y^(5-5)
=y^0
=1
2007-02-12 13:49:10 · answer #7 · answered by dla68 4 · 0⤊ 0⤋