answers:
x<6-3e
x<6-e^-3
x>6-3e
x<6+e^-3
2007-02-12 05:01:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Make each side the exponent of e.
e^(ln(x-6)) < e^(-3)
Simplify the left side to x-6, since e^lnx = x.
x - 6 < e^(-3)
Now solve for x, and you have
x < 6 + e^(-3)
2007-02-12 05:13:47 · answer #1 · answered by Anonymous · 1⤊ 0⤋
x<6+e^-3
2007-02-12 05:05:16 · answer #2 · answered by bozo 4 · 2⤊ 0⤋
You undo besides the fact that is finished to the variable. In different words, 6 is subtracted from "x" so which you upload 6 to "x", then you definately would desire to do a similar to the different area to stability it meaning you upload 6 to -3 which equals 3. The ending answer is x<3
2016-11-03 06:10:50 · answer #3 · answered by ? 4 · 0⤊ 0⤋
ln (x - 6) < (-3)
x - 6 < e ^ (-3)
x < 6 + e ^ (-3) which is final option choice.
2007-02-12 05:41:16 · answer #4 · answered by Como 7 · 0⤊ 0⤋
ln(x-6)<-3 is equivalent to x-6
2007-02-12 05:14:28 · answer #5 · answered by santmann2002 7 · 0⤊ 0⤋