the log7 7^9=1
answers: true or false?
solve 2x=15
answers: log2/log15
log15/log2
log15
log2
2007-02-12 04:18:23 · 4 answers · asked by jj c 1 in Science & Mathematics ➔ Mathematics
log[base 7](7^9) = 1
True or false?
The answer is false, because log[base 7](7^9) = 9log[base 7](7) = 9
2^x = 15 means
log[base 2](15) = x
Which is equal to
x = log(15)/log(2)
2007-02-12 04:32:57 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
A logarithm is set up like this:
log(base n) of n^x = x.
For instance, log(base 10) 1000 = 3, because 10^3 = 3.
So log(base7) of 7^9 = 9.
As for the second one...I don't know, because 2x = 15 would be solved as x = 15/2, and none of those are equal to 15/2.
2007-02-12 04:34:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
log7 7^9 = 1
9 * log7 7 = 1
9 * 1 = 1
9 != 1
2007-02-12 04:46:25 · answer #3 · answered by s3r3ux 1 · 1⤊ 0⤋
whaoo!! this questions scare me dude!!!
2007-02-12 04:26:30 · answer #4 · answered by jero j 2 · 0⤊ 2⤋