answers:
13=x
13
no solution
2007-02-12 03:53:34 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
logs and exponents are inverse operations or in other words a power of 3 and the log base three cancel.
e.g: logbase_y ( y ^ x) = x = y ^ (logbase_y [x])
so to solve this one take
3 ^ (logbase_3 [x - 4]) > 3 ^ 2
2007-02-12 04:15:11 · answer #1 · answered by WOMBAT, Manliness Expert 7 · 0⤊ 0⤋
Addition sources of logs: log3(x+12)+log3(x+4)=2 --> log3((x+12)(x+4)) To eliminate the log base 3: 3^log3((x+12)(x+4)) = 3^2 --> (x+12)(x+4) = 9 some algebra: x^2 + 16x + 40 8 = 9 --> x^2 + 16x + 39 = 0 --> (quadratic formula) --> x= -3 examine: log3(9) + log3(a million) = 2 + 0 = 2... QED
2016-12-04 02:12:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Raise 3 to the power of both sides, you get
3^[log3 (x-4)] > 3².
You can take it from there. Remember, base^log a = a. (The log is the inverse of the exponential funcion.)
2007-02-12 03:58:18 · answer #3 · answered by Anonymous · 1⤊ 0⤋
log3 (x-4) > 2
3^(log3 (x-4)) >3^ 2
x-4 > 9
x > 13, or equivalently 13 < x
2007-02-12 04:03:09 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋