I can't quite remember what exactly makes a glucose molecule D or L. When in the Fisher projection but not in ring form, a glucose molecule has a chain of 6 carbons. #1 carbon is the CHO and #6 C is the CH2OH. Each carbon in between has a OH and a H attached to it. For the D-glucose, the OH is: #2 - right; #3 - left; #4 - right; #5 - right. I know that for L-glucose, the OH on one of the carbons is reversed (i.e. it goes from on the right to on the left). I can't remember which carbon it flips on: #2 or #5.
2007-02-12
03:28:23
·
3 answers
·
asked by
Anonymous
in
Science & Mathematics
➔ Chemistry