State six ordered pairs for this function f(x)=x^2+14x+45?

Question

This math stuff...Plz help Im lost..

Answer 1

An "ordered pair" is merely a point of the graph of the function. Select 6 different values of x, replace x with each of these values and you will get 6 different points in this form (x,f(x)).
Example:
x=1: f(1)=1^2+14*1+45=1+14+45=60: (1,60) is one point(="ordered pair").

Answer 2

What you do is plug in numbers for x to get the y-values. Here are some examples:
f(0)=(0)^2+14(0)+45
f(0)=45
(0,45)

x^2+14x+45=0
(x+9)(x+5)=0
x=-9 and -5
(-9,0) and (-5,0)

I hope this helps and good luck with your math class!

Answer 3

Just plug in a value for x and find f(x) which is y. Write the ordered pairs in the form (x,y). Here are some:

(0,45),
(1,60)
(2, 77)
(-1, 32)
(-2, 21)
(3, 96)

Answer 4

f(x)=x^2+14x+45

Chose 6 X values that make the math easy.
(-1,
(1,
(0,
(-2,
(-3,
(2,

Put these in for x calculate the result, -1^2 is 1,+14(-1) is -14 + 45=32

(-1,32)
(1,60)
(0,45)
(-2,
(-3,
(2,

Answer 5

Get a graphing calulator. They're marvelous.
OK:
(-3,-28)
(-2,-19)
(-1,-8)
(0, 5)
(1, 20)
(2,37)
Just type in the function (in Y=), then go to 2nd Table, and voila, tons of ordered pairs.