if the volume is 270cm3, what is the height of the solid of a base with l=10cm, w=9cm
2007-02-12 02:57:52 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3cm
(V = l x w x h)
2007-02-12 03:01:32 · answer #1 · answered by Bill C 2 · 0⤊ 0⤋
The formula for the volume of a solid is:
V=(l)(w)(h)
where:
l: length of the base
w:width of the base
h: height of the solid
So if you substitute all the variables with the values given in the problem:
270 cm3=(10cm)(9cm)h
and solving for the height:
h=270cm3/(10cm)(9cm)
so the height equals 3cm
2007-02-12 03:13:02 · answer #2 · answered by omma2289 2 · 0⤊ 0⤋
The height is 3 centimeters because the volume of a solid is length times width times height. (V=l*w*h)
9 times 3 times 10 is 270
2007-02-12 03:03:21 · answer #3 · answered by Shockwave48 2 · 0⤊ 0⤋
Area of base = A = 10 x 9 cm² = 90 cm²
Area of base x height = Volume
90 x h = 270
h = 3 cm
Height = 3 cm
2007-02-12 03:02:55 · answer #4 · answered by Como 7 · 0⤊ 0⤋
Volume of cylinder = πr²h r = 5 h = 12.4 V = π(5)²(12.4) = 973.4 cubic feet The wrong answers are for failing to square the radius and for selecting the wrong units.
2016-05-24 00:50:02 · answer #5 · answered by Anonymous · 0⤊ 0⤋
volume = length * width * height
Therefore:
height = volume / (length*width) = 270 cm3 / (10 cm * 9 cm) = 3 cm.
2007-02-12 03:03:49 · answer #6 · answered by vjstrugar 2 · 0⤊ 0⤋
h*10*9=270
h*90=270
h=270/90
h=3cm
2007-02-12 03:11:39 · answer #7 · answered by Akshav 3 · 0⤊ 0⤋