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2007-02-12 00:34:36 · 6 answers · asked by Christian1234 1 in Science & Mathematics Mathematics

6 answers

____x^2-x-2_________
x-2/x^3-3x^2+3
x^3-2x^2
--------------
-x^2+3
-x^2+2x
-----------
-2x-3
-2x+4
-----------
-7
Ans: Quotient=x^2-x-2 Remainder= -7

2007-02-12 00:45:04 · answer #1 · answered by Maths Rocks 4 · 1 0

x³ - 3x² + 3 divided by x-2
x(x² - 3x + 3) / x - 2
Factoring:
x(x - 2)(x -1) over x - 2 = x(x - 1)
><

2007-02-12 01:33:01 · answer #2 · answered by aeiou 7 · 0 0

=(X^2-X-2)(X-2)+1

2007-02-12 23:26:07 · answer #3 · answered by rose rose 1 · 0 0

I don't know, here is what I keep getting:

x^2 - x - 2 - (1/x-2)

When you set up your problem, you would set it up as the following:

x-2 / x^3 - 3x^2 + 0x + 3

And then you divide
....................x^2 - x - 2 - (1/x-2)
........---------------------------------
x - 2 | x^3 - 3x^2 + 0x + 3
..........x^3 - 2x^2
...................-x^2 + 0x
..................- x^2 - 2x
.......................... -2x + 3
.............................-2x + 4
.....................................-1
remainder -1/x-2

2007-02-12 00:56:02 · answer #4 · answered by Jason 3 · 0 0

quotient: x ^ 2 - x - 2
reminder: -1

2007-02-12 00:47:15 · answer #5 · answered by naresh 2 · 0 0

x^2 - x -2
_________________
x-2 / x^3 - 3x^2 + 3
.......x^3 - 2x^2
----------------------------
..................-x^2 + 3
..................-x^2 + 2x
-----------------------------
.......................... -2x +3
.......................... -2x +4
-----------------------------
..................................-1

(x^3 - 3x^2 + 3)/(x-2) = (x^2 - x -2) + 1/(x-2)
remainder = -1

2007-02-12 00:59:36 · answer #6 · answered by Mena M 3 · 0 0

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